Question 329357
{{{(u^8z^7)/(z^(-3)u^(-2)) =u^(8-(-2))z^(7-(-3))}}}
{{{(u^8z^7)/(z^(-3)u^(-2)) =u^(10)z^(10)}}}
{{{(u^8z^7)/(z^(-3)u^(-2)) =(uz)^(10)}}}
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{{{P(-1/2) = 2(-1/2)^4 + (-1/2)^3 + 12}}}
{{{P(-1/2)=2(1/16)-1/8+12}}}
{{{P(-1/2)=1/8-1/8+12}}}
{{{P(-1/2)=12}}}