Question 329422
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Let *[tex \Large r] represent the speed of the boat in still water.  Then *[tex \Large r\ -\ 2] represents the upstream speed and *[tex \Large r\ +\ 2] represents the downstream speed.  Let *[tex \Large t] represent the elapsed time for the upstream trip, then *[tex \Large 17\ -\ t] represents the elapsed time for the downstream trip.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t\ =\ \frac{27}{r\ -\ 2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 17\ -\ t\ =\ \frac{27}{r\ +\ 2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t\ =\ 17\ -\ \frac{27}{r\ +\ 2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{27}{r\ -\ 2}\ =\ 17\ -\ \frac{27}{r\ +\ 2}]


Just solve for *[tex \Large r].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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