Question 329392
3x-2y=10
5x+2y=6
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(adding) 8x = 16
=> x = 16/8 = 2
Hence, from equation (i), we get
3x2 - 2y = 10
=> 6 - 2y = 10
=> -2y = 10 - 6 = 4
=> y = 4/(-2) = -2
Hence, the required solution set is (2, -2)