Question 329265
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2\ -\ 2x -\ 1\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ 2\ \ ], *[tex \LARGE b\ =\ -2\ \ ], and *[tex \LARGE c\ =\ -1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-(-2)\ \pm\ \sqrt{(-2)^2\ -\ 4(2)(-1)}}{2(2)}]


You can do your own arithmetic.  Leave it in simplest radical form for the exact answers.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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