Question 329251
please walk me thru 
[(t-3)/(t-2)]/[(4t-12)/(t+1)]
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[(t-3)/(t-2)]*[(t+1)/(4(t-3))]
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Cancel any factor common to a numerator and a denominator,
such as (t-3), to get:
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[1/(t-2)]*[(t+1)/4]
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= (t-1)/(4(t-2))
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Cheers,
Stan H.
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