Question 329160
{{{(2)/(9z^3) + (1)/(6z^2)=(1/3z^2)(2/(3z)+1/2)}}}
{{{(2)/(9z^3) + (1)/(6z^2)=(1/3z^2)(4/(6z)+(3z)/(6z))}}}
{{{(2)/(9z^3) + (1)/(6z^2)=(1/3z^2)((4+3z)/(6z))}}}
{{{(2)/(9z^3) + (1)/(6z^2)=(4+3z)/(18z^3)}}}