Question 329179
Solve each system by substitution
{{{x/6 + y/10 = 3}}}
:
{{{(5x)/16 - (3y)/16 = 15/8}}}
:
Get rid of those annoying fractions
:
Mult 1st equation by 30, results:
5x + 3y = 90
3y = 90 - 5x
divide thru by 3
y = 30 - {{{5/3}}}x; use this for substitution
:
Mult 2nd equation by 16, results
5x - 3y = 2(15)
5x - 3y = 30
Substitute for y
5x - 3(30 - {{{5/3}}}x) = 30
5x - 90 + 5x = 30
5x + 5x = 30 + 90
10x = 120
x = 12
:
Find y using eq: 5x - 3y = 30; replace x with 12
5(12) - 3y = 30
60 - 3y = 30
-3y = 30 - 60
-3y = -30
y = +10
:
:
Check solutions in the first original equation
{{{x/6 + y/10 = 3}}}
{{{12/6 + 10/10 = 3}}}