Question 329150
{{{(2x^2-8)/(x^2-x-2)=(2(x^2-4))/((x-2)(x+1))}}}
{{{(2x^2-8)/(x^2-x-2)=(2*cross((x-2))(x+2))/(cross((x-2))(x+1))}}}
{{{(2x^2-8)/(x^2-x-2)=(2(x+2))/(x+1)}}}