Question 329071
I assume you're looking for the zeros of the quadratic equation?
{{{(1/8)h^2-(1/2)h+1=0}}}
{{{h^2-4h+8=0}}}
{{{h^2-4h+4+4=0}}}
{{{(h-2)^2+4=0}}}
{{{(h-2)^2=-4}}}
{{{h-2=0 +- 2i}}}
{{{highlight(h=2 +- 2i)}}} where {{{i=sqrt(-1)}}}
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To verify, plug the solution into the equation.