Question 329018
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I'm guessing that you intended to write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{2n\ -\ 88}\ =\ \sqrt{\frac{n}{6}}]


Use parentheses next time so that it is clear which parts of your expression go under the radical and which do not.  For example, your rendering could be interpreted as:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{2n}\ -\ 88\ =\ \frac{\sqrt{n}}{6}]


Presuming you meant:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{2n\ -\ 88}\ =\ \sqrt{\frac{n}{6}}]


Square both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2n\ -\ 88\ =\ \frac{n}{6}]


Now just solve for *[tex \Large n]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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