Question 329035
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Area of a rectangle is length times width


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ lw\ =\ 2w\,\cdot\,w\ =\ 2w^2\ =\ 32]


Solve *[tex \LARGE 2w^2\ =\ 32] for *[tex \LARGE w] then multiply by 2.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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