Question 329014
<font face="Garamond" size="+2">


Use the quadratic formula.  The solutions of 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ax^2\ +\ bx +\ c\ =\ 0]


are


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}].


Your problem


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 7x +\ 9\ =\ 0]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ 1\ \ ], *[tex \LARGE b\ =\ -7\ \ ], and *[tex \LARGE c\ =\ 9]


Just put the values into the formula and do the arithmetic.  Leave it in simplest radical form for the exact answer, and run them through a calculator to get the numeric approximations.  Refer to your instructor for the desired precision on your approximations.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>