Question 329015
x^2+12x+1=36
x^2+12x+1-36=0
x^2+12x-35=0
find the roots of the equation using formula
{{{x=(-b+-sqrt(b^2-4ac))/(2*a)}}}
a=1b=12c=-35

x = [-12 +- sqrt(144 -4*-35)]/2
..
x = [-12 +- sqrt(284)]/2
..
x = [-12 +- 2sqrt(71)]/2
..
x = [-6 +- sqrt(71)]