Question 328932
{{{(1/36)^(1/2)+(1/64)^(-5/6)}}}
The reciprocal gets rid of the neg exponent
{{{(1/36)^(1/2)+ 64^(5/6)}}}
^(1/2) is the square root
{{{sqrt(1/36) + 64^(5/6)}}}
:
{{{(1/6) + 64^(5/6)}}}
The 6th root of 64 is 2
{{{(1/6) + 2^5}}}
{{{(1/6) + 32}}} = 32{{{1/6}}}