Question 328931
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ k(a)\ =\ \sqrt{a\ +\ 1}]


Just plug in the value in the parentheses and do the arithmetic.  Remember, the domain of square root is all reals greater than 0, hence any value of the independent variable that makes the radicand less than zero makes the function undefined.


Domain:





*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ][*[tex \LARGE -1,\infty])



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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