Question 328813
No, the equation is in vertex form, {{{y=a(x-h)^2+k}}} where (h,k) is the vertex.
Comparing,
(h,k)=(-9,-6)
The vertex lies on the axis of symmetry, {{{x=-9}}}
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{{{drawing(300,300,-14,2,-12,4,grid(1),circle(-9,-6,.3),blue(line(-9,-20,-9,20)),graph(300,300,-14,2,-12,4,(x+9)^2-6))}}}