Question 328754
how many gallons each of 25% alcohol and 35% alcohol should be mixed to get 10 gallons of 32% alcohol?
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Equation:
alcohol + alcohol = alcohol
0.25 x + 0.35(10-x) = 0.32*10
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Multiply thru by 100 to get:
25x + 35*10 - 35x = 32*10
-10x = -3*10
x = 3 gallons (amt. of 25% alcohol needed in the mixture)
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10-x = 7 gallons (amt. of 35% alcohol needed in the mixture)
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Cheers,
Stan H.
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