Question 328744
{{{y=(1+ln(x))*(2-x^2)^(-1)}}}}
Use the product rule,
y=fg
y'=fg'+gf'
{{{dy/dx=(1+ln(x))(-1)(2-x^2)^(-2)*(-2x)+(2-x^2)^(-1)*(1/x)}}}
{{{dy/dx=(2x(1+ln(x)))/(2-x^2)^2+1/(x(2-x^2))}}}