Question 328609
gof =g[f(x)]


This means to take the function for f(x) and plug it in to replace x the formula for g(x).


g(x) = 2x-5, while f(x)-{{{sqrt(x+1)}}}  (assuming I've interpreted your problem correctly!)


g[f(x)]= g[{{{sqrt(x+1)}}}]
={{{2*sqrt(x+1)-5}}}


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