Question 328669
emily require x hours
Max requires x+5 
..
emily can do the 1/x of the job in 1 hour
max can do 1/(x+5) of the job in 1 hour
..
Together they will do in {{{1/x + 1/(x+5)}}} hours
LCM = x(x+5)
{{{ ((x+5)+x)/(x*(x+5))}}}
{{{(2x+5)/(x*(x+5))=6}}}
{{{(2x+5)=(6*x*(x+5))}}}
{{{2x+5=6x^2+30x}}}
{{{6x^2-2x+30x-5}}}
{{{6x^2+28x-5}}}
find the roots of the equation x1,x2 using quadratic equation
{{{x1=(-b+sqrt(b^2-4*a*c))/(2*a)}}}
{{{x1=(-28+sqrt(28^2+120))/12}}}
{{{x2=(-28-sqrt(28^2+120))/12}}}

x1= 0.17 hours --- Emily does it in 0.17 hours
x2= -4.8 hours ignore this value