Question 328451
1/4(6b+2)-2/3(3b-2)
(6b+2)/4-2(3b-2)/3
(6b+2)/4-(6b-4)/3
[3(6b+2)-4(6b-4)]/4*3
[18b+6-24b+16]/12
[-6b+22]/12
[-3b+11]/6 ans.