<PRE><B>Question 328570</B>
What is 3x+6 over 14 times 7x squared over x3+2x squared equals?
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[(3x+6)/14]*[7x^2/(x^3+2x)]
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= [3(x+2)/14]*[7x^2/(x(x^2+2))]
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Cancel any factor that is common to a numerator and a denominator
such as 7,and x.
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= [[3(x+2)/2]*[x/(x^2+2)]
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= [3x(x+2)]/[2(x^2+2)]
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Cheers,
Stan H.
</PRE>