Question 328530
Isolate the exponential expression by dividing both sides by 4.

43 = 4e^(3x)

43/4 = e^(3x)

Now take the natural log of both sides of the equation.

Let ln = natural log

ln(43/4) = ln[e^(3x)]

ln(43/4) = 3xlne

We now solve for x. To do so, divide both sides by lne.

ln(43/4) divided by lne = x

NOTE: lne = 1 by definition

ln(43/4) divided by 1 = x 

ln(43/4) = x

2.374905755 = x

Round to the nearest tenths.

So, x is approximately 2.4