Question 328529
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b(x)\ =\ \frac{\log(x)}{\log(b)}\ =\ \frac{\ln(x)}{\ln(b)].


You need:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_{6.4}(39)\ =\ \frac{\log(39)}{\log(6.4)}\ =\ \frac{\ln(39)}{\ln(6.4)].


You can do the calculation with either base 10 or natural logs, makes no difference.  Oh, and I don't do arithmetic.  That's for you to do.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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