Question 328500
The velocity ds/dt (in meters/second) of a projectile is given by 
ds/dt=-9.8t+16 
Find the displacement s of the object after 4 seconds if the initial displacement is 48 m. 
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s = the integral of ds/dt
s = -4.9t^2 + 16t + C
C = 48 m, the initial displacement
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s(t) = -4.9t^2 + 16t + 48
s(4) = -4.9*16 + 64 + 48
s(4) = 33.6 meters