Question 328418
1.{{{x^2 + y^2 = 58}}}
2.{{{y = x^2 - 2}}} 
From eq. 2,
{{{x^2=y+2}}}
Substitute into eq. 1,
{{{y+2+y^2=58}}}
{{{y^2+y-56=0}}}
{{{(y-7)(y+8)=0}}}
Two solutions for y.
{{{y-7=0}}}
{{{y=7}}}
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{{{y+8=0}}}
{{{y=-8}}}
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.Now solve for x.
{{{x^2=y+2}}}
{{{x^2=7+2=9}}}
{{{x=0 +- 3}}}
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{{{x^2=-8+2}}}
{{{x^2=-6}}}
No solution.
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(-3,7) and (3,7) are the solutions
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{{{drawing(300,300,-8,8,-6,10,grid(1),circle(3,7,0.25),circle(-3,7,0.25),graph(300,300,-8,8,-6,10,sqrt(58-x^2),x^2-2),graph(300,300,-8,8,-6,10,-sqrt(58-x^2))))}}}