Question 328423
Probability B fails given A fails, P(B|A), is given as .06

P(A)=.01

P(B)=.03

part a would be the probability A and B fail, P(A and B)

P(B|A)=P(A and B)/P(A)

.06=P(A and B)/.01

P(A and B)=.0006

part b, P(A|B)=P(A and B)/P(B)

We now have P(A and B)=.0006 from part a. Use this to answer part b.

P(A|B)=.0006/.03=.02

part c, the events are independent if the occurence of one does not affect the occurence of the other. That is, if P(B|A)=P(B) or P(A|B)=P(A) they are independent.

Are they the same?.