Question 328390
{{{y^2=(2/3)y+4/3}}}
{{{y^2-(2/3)y-4/3=0}}}
Multiply both sides by 3.
{{{3y^2-2y-4=0}}}
Use the discriminant,
{{{D=b^2-4ac}}}
{{{D=(-2)^2-4(3)(-4)}}}
{{{D=4+48}}}
{{{D=52}}}
Since the discriminant is positive, the solutions are two distinct real roots.
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{{{graph(300,300,-5,5,-5,5,x^2-(2/3)x-4/3)}}}