Question 328269
{{{(3a^7+7)/(a^2-2a-8)  -    (7+3a^2)/(a^2-2a-8)=(3a^7-3a^2)/(a^2-2a-8)}}}
{{{(3a^7+7)/(a^2-2a-8)  -    (7+3a^2)/(a^2-2a-8)=3a^2(a^5-1)/((a-4)(a+2))}}}
{{{(3a^7+7)/(a^2-2a-8)  -    (7+3a^2)/(a^2-2a-8)=(3a^2(a-1)(a^4+a^3+a^2+a+1))/((a-4)(a+2))}}}