Question 328292
Factor:
{{{27-8u^3}}} Rewrite this as:
{{{-(8u^3+27)}}} Notice that this is the sum of two cubes:
{{{-((2u)^3+(3)^3)}}} The sum of two cubes can be factored thus:
{{{A^3+B^3 =  (A+B)(A^2-AB+B^2)}}} where {{{A = 2u}}} and {{{B = 3}}} so...
{{{-(8u^3+27) = highlight(-(2u+3)(4u^2-6u+9))}}}