Question 328231
 Given the following sample information, test the hypothesis that the treatment means are equal at the 0.05 significance level. 
Treatment 1
8
11
10 
Treatment 2
3
12
11
8
4 
Treatment 3
11
20
18
12 

a. Set up the null hypothesis and alternative hypothesis. 
Ho: the means are all equal
Ha: At least one of the means is not equal
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b. State the decision rule.
df numerator = k-1 = 3-1 = 2
df denominator = N-k =  12-3 = 9 
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F = 4.2565


c. Use Excel or Megastat to complete an ANOVA table. Copy the table and paste it here, not as a separate attachment.
test stat: F = 4.6901
p-value = 0.0402
Factor
df = 2
SS = 134.05
MS = 67.025
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Error:
df = 9
SS = 128.62
MS = 14.29
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Cheers,
Stan H.
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