Question 328224
Factor first,
{{{((x^2-7x+12)/(x^2-6x+8))((x^2-5x+6)/(x^2-9x+18))=(((x-4)(x-3))/((x-4)(x-2)))*(((x-3)(x-2))/((x-3)(x-6)))}}}
{{{((x^2-7x+12)/(x^2-6x+8))((x^2-5x+6)/(x^2-9x+18))=((cross((x-4))(x-3))/(cross((x-4))cross((x-2))))*((cross((x-3))cross((x-2)))/(cross((x-3))(x-6)))}}}
{{{((x^2-7x+12)/(x^2-6x+8))((x^2-5x+6)/(x^2-9x+18))=highlight((x-3)/(x-6))}}}