Question 328236
Let X be the amount of water (0% argyol).
Let Y be the amount of 18% argyol.
1.{{{X+Y=10}}}
.
.
.
{{{0(X)+18(Y)=12(10)}}}
{{{18Y=120}}}
{{{highlight(Y=20/3)}}}liters
Then from eq. 1,
{{{X+20/3=30/3}}}
{{{highlight(X=10/3)}}}liters