Question 328212
(4x^7y^4/5a^6b^4)/(3x^3y^3/2a^3b^2) invert the second fraction & multiply.
(4x^7y^4/5a^6b^4)(2a^3b^2/3x^3y^3)
4*2x^4y/5*3a^3b^2
8x^4y/15a^3b^2 ans.