Question 328064
The area of a circular sector is {{{A=1/2*r^2*(theta)}}}

We are given A=40 and r=12. We have to solve for theta.

{{{40=1/2*(12)^2*(theta)}}}

{{{40=72*(theta)}}}

{{{5/9=(theta)}}} radians

This is equal to {{{(5/9)(180/(pi))=100/(pi)=31.83}}} degrees