Question 328111
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Use the point-slope form of an equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the given slope.


Then solve for *[tex \Large y], that is, put the equation in *[tex \Large y\ =\ mx\ +\ b]


In general, for an equation in point-slope form, you can change to slope-intercept by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ (y_1\ -\ mx_1) ]


Where *[tex \Large y_1\ -\ mx_1] becomes the *[tex \Large b] in *[tex \Large y\ =\ mx\ +\ b]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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