Question 328048
You have to be able to read this. First you must
know that **logs are exponents**.
If you have {{{a^b}}}, then {{{b}}} is a log to the base {{{a}}}
{{{log(9,x) = -3}}} says the log to the base {{{9}}} which gives 
me {{{x}}} is {{{-3}}}.
You know {{{-3}}} is the exponent because 
log(something) = {{{-3}}} 
If {{{-3}}} is the exponent, and {{{9}}} is the base, I can write
{{{9^(-3) = x}}}
Now you have to know what to do with a negative exponent
The rule is:
{{{a^(-b) = 1/a^b}}}, so
{{{9^(-3) = 1/9^3}}}, and
{{{1/9^3 =1/ (9*9*9)}}}
{{{1/(9*9*9) = 1/729}}}
So far, I have
{{{9^(-3) =  1/729}}}, so
{{{x = 1/729}}}
Remember, also, that there is no way you could have
something like
{{{log(10,-10) = x}}}
This is saying {{{10^x = -10}}}
There is no possible {{{x}}} that can give you a minus result
Good luck - just pound away at this stuff- It's like
cement- It will crumble after a while