Question 327968
a)P(all work)={{{(0.94)^6=0.6899}}}
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b)P(all fail)={{{(0.06)^6=0.00000004666}}}
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c)P(only one fails)=P(#1 fails) or P(#2 fails) or ... P(#6 fails)
P(only one fails)=P(#1 fails) +P(#2 fails)+ ... +P(#6 fails)
P(only one fails)={{{0.06+0.06+0.06+0.06+0.06+0.06}}}
P(only one fails)={{{0.36}}}