<PRE><B>Question 327930</B>
3y-1&lt;8y-3


Subtract 8y from each side:
3y-8y-1&lt;8y-8y-3
-5y-1&lt;-3


Add +1 to each side
-5y-1+1&lt;-3+1
-5y&lt;-2


Divide both sides by -5, and don&#39;t forget to REVERSE the sign because you divided by a NEGATIVE number:
{{{(-5y)/(-5) &gt; (-2)/(-5)}}}
{{{y &gt; 2/5}}}


Set builder notation is {y|y&gt;2/5},  which is read:
THE SET of all values of Y, SUCH THAT, y&gt;2/5.


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus</PRE>