Question 327900
Solve: {{{x^2+2x =  8}}} by completing the square.
{{{x^2+2x= 8}}} Add the square of half the x-coefficient. {{{(2/2)^2 = 1}}}
to both sides.
{{{x^2+2x+1 = 8+1}}} Factor the left side.
{{{(x+1)^2 = 9}}} Take the square root of both sides.
{{{x+1 = 3}}} or {{{x+1 = -3}}} Subtract 1 from both sides in each solution.
{{{highlight(x = 2)}}} or {{{highlight(x = -4)}}}