Question 327860
e.125^3-8s^3

Difference of two cubes formula: a^3-b^3=(a-b)(a^2+ab+b^2)
125^3-8s^3= (5-2s)(25+10s+4s^2)


f.5c^2+2c-3
This trinomial is of the form ax^2+bx+c with a=5,b=2,and c= -3.
Find two numbers whose product is a*c or 5*-3= -15, and whose sum is b or 2.
The numbers are 5 and -3.
Write +2c as +5c-3c 

= 5c^2+5c-3c-3
Now factor by grouping
= 5c(c+1)-3(c+1)
= (c+1)(5c-3)


g.16u^4-v^4

=(4u^2-v^2)(4u^2+v^2)
=(2u-v)(2u+v)(4u^2+v^2)