Question 327852
A launched rocet has an altitude in meters given by the polynomial h+vt-4,9t to the 2nd power.where h is the height in meters, from which the launch occurs, at a valacity v in meters per seconds, and t is the number of seconds for which the rocket is airborne if a rocket is launched from the top of a tower 60 meters high with an intial upward speed of 80 meters per second what will its height be in 2 seconds? 
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Equation, height as a function of time:
{{{h(t) = h + vt -4.9t^2}}}
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based on the info given by the problem:
h = 60 meters
v = 80 meters per sec
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{{{h(t) = 60 + 80t -4.9t^2}}}
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So, to answer the question, set t to 2 and solve:
{{{h(t) = 60 + 80t -4.9t^2}}}
{{{h(2) = 60 + 80(2) -4.9(2)^2}}}
{{{h(2) = 60 + 160 -4.9(4)}}}
{{{h(2) = 60 + 160 -19.6}}}
{{{h(2) = 220 -19.6}}}
{{{h(2) = 200.4}}} meters