Question 327812


{{{(x+2)^2=1}}} Start with the given equation.



{{{x+2=""+-sqrt(1)}}} Take the square root of both sides.



{{{x+2=sqrt(1)}}} or {{{x+2=-sqrt(1)}}} Break up the "plus/minus" to form two equations.



{{{x+2=1}}} or {{{x+2=-1}}}  Take the square root of {{{1}}} to get {{{1}}}.



{{{x=-2+1}}} or {{{x=-2-1}}} Subtract {{{2}}} from both sides.



{{{x=-1}}} or {{{x=-3}}} Combine like terms.



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Answer:



So the solutions are {{{x=-1}}} or {{{x=-3}}}.