Question 327545
The perimeter is 28 meters and its length is 2 meters more than twice it width. What is its length?


Let the width be W


Then the length = 2W + 2, since the length is 2 meters more than twice its width  


Since perimeter = 28 m, we will have: 2W + 2(2W + 2) = 28 ----> 2W + 4W + 4 = 28 ---> 6W = 24 ----> W = {{{24/6}}} = 4 m


Since W, or width = 4 m, then length = 2(4) + 2, or {{{highlight_green(10)}}}, since length is 2 m more than twice the width.