Question 327420
Rate*Time=Distance
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{{{R1=6}}} 
{{{R2=10}}}
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With the 3 hour head start, Cyclist 1 is 18 miles ahead of Cyclist 2.
t is measured from the time Cyclist 2 starts.
{{{D1=18+6t}}}
{{{D2=10t}}}
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Find t when {{{D1=D2}}}.
{{{18+6t=10t}}}
{{{4t=18}}}
{{{t=9/2}}} or 4.5 hrs