Question 37946
A line passes through the point (8,6) and has a slope of 6 . 
Write an equation for this line in (x,y)-coordinates.
To find the equation of a line given the slope and one point 
we can use the point-slope formula {{{y - y1 = m(x - x1)}}}
Lets make point (8,6) = (x1,y1) 
And m = 6 (this is the slope.)
Now we just plug in the values...
{{{y - 6 = 6(x - 8)}}}
Now we perform the indicated operations...
{{{y - 6 = 6x - 48)}}}
Then add 6 to both sides of the equation...
{{{y = 6x - 42)}}}
And this is the final equation.
I hope this helps.
Good Luck!