Question 327473
10CM TO THE 3RD POWER OF A NORMAL BLOOD SPECIMEN CONTAINS 1.2G OF HEMEGLOBIN. HOW MANY GRAMS DOES 18CM TO THE 3RD POWER OF THE SAME BLOOD CONTAIN?
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Equation:
(10cm)^3 has 1.2G of Hemeglobin.
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(18cm)^3 has xG of Hemeglobin.
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Solve for "x":
Using a proportion:
x/(18^3) = 1.2/10^3
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x = (18^3)(1.2/10^3)
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x = 1.8^3*1.2
x = 5.832*1.2
x = 6.9984G
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Cheers,
Stan H.
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