Question 327356
Let the side of the squares be l cm.
Then, the length of the rectangle = 3 times the side of a square
                                  = 3l cm
The width of the rectangle  = side of the square = l cm
Given that, Perimeter of the rectangle = 64 cm.
 2 (length + width) = 64
2 (3l + l) = 64
2(4l) = 64
8l = 64
l = 64/8 
l = 8 cm

side of the one of squares = 8 cm
Therefore the area of one of the squares = 8 X 8 = 64 sq.cm