Question 326995
Let's write an equation for this problem, "stopping distance d of a car after the brakes are applied varies directly as the square of the speed r": {{{d=c*r^2}}}. With c being the constant. Plugging in 70mph and 270feet you get: {{{270feet=c*(70^2)}}}. Divide both sides by 70^2 to get c=0.055. Now that you have found c, let's find the stopping distance of the car if it where traveling at 20mph. The equation {{{270=c*(70^2)}}} becomes {{{d=0.055*(20^2)}}} after you plug in the c and r. Then you find that {{{d=22 feet}}}. Hope this helps :D!!!!
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