Question 327349
You can pull out common variables and numbers from each of these terms. They share {{{3xy^2}}}. Pulling out from all of them makes [(3*x^3*y^2) – (3*x^2*y^2) + (3*x*y^2)] become {{{3xy^2(x^2-x+1)}}}. There is no way you can factor x^2-x+1 without using imaginary numbers, so you can stop there :) Thus, {{{3xy^2(x^2-x+1)}}} is your answer. ****---->If you need anymore help, please visit my website at http://myonlinetutor.webs.com and become a member ^0^!